1. At t=0, a bandicoot is running forward at 3 m/s. It has an acceleration of 1 m/s^2 backward for 2 seconds, and then continues at a constant velocity for another 2 seconds. a. What is its velocity at t = 2 s?
b. What is its velocity at t = 4 s?
c. What is its position at a t = 2 s?
d. What is its position at t = 4 s?

because it says use -2,0,and 2 for x, we can plug those numbers into the equation. y/4=3/4(-2)+2   y/4= -1 1/2 +2 now to get x by itself, we can multiply each side by 4. y=-6+8 which equals y=2 when x=-2. now you can do the same thing with 0 and 2 as x. you get y=8 when x=0 and y=14 when x=2.

x   |   y

-2 |   2

0   |   8

2   |   14

this is a good question! i'll do some research and come back when i have the answer!

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .