The spreading out of waves after they pass through a narrow opening is?

there are no correct statementd on the list of choices you provided.

i don't understand is there any other way you can rephrase it plz let me know in the comments and i will do it.

explanation:

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j