Near the surface of the earth, a rock is launched straight up. The initial velocity of the rock has a vertical component of 67 m/s. How long will it take the rock to reach the highest point in its path?
O 7 seconds
O 657 seconds
O 57 seconds
O 0 seconds

answer; equivalent to a one(1) horsepower motor;

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s