A parallel plate capacitor is constructed with a dielectric slab with κ = 1.5 inserted between the plates. The area of each plate is 5 cm2, and the distance between the two plates is 1 mm. Assume the infinite plane approximation. 1) If we fix the charge on the capacitor to be Q = 6×10-11 C, what is the potential difference between the top and bottom plates? Note that in the region containing the dielectric medium, the electric field is E = E0 / κ, where E0 is the electric field in vacuum.

The value is

Explanation:

From the question we are told that

The dielectric constant is k = 1.5

The area of each plate is

The distance between the plates is

The charge on the capacitor is

Generally the electric field in a vacuum is mathematically represented as

Generally is the voltage of the capacitor which is mathematically represented as

Here is the capacitance of the capacitor in a vacuum which is mathematically represented as

Here is a constant with value

=>

=>

So

So

=>

The electric field when the dielectric slab is inserted is mathematically represented as

=>

=>

Generally the electric field between the plates is mathematically evaluated as

=>

=>

Generally the potential difference between the plates is

=>

a.) travels faster in solids because the particles are closer together.

air is a gas water is a liquid