A 25.0 kg bag of peat moss sits in the back of a flatbed truck, driving up a hill. The bag experiences a 225N normal force. The maximum acceleration the truck can have so the bag does not slip is 2.40 m/s2 . Calculate the (a) angle of the hill relative to horizontal and (b) coefficient of static friction between the bag and the truck. (c) The truck is now travelling on level ground at constant speed. The sand bag is tossed forward sliding along the truck bed with a horizontal speed of 2.55 m/s. If the coefficient of kinetic friction is 0.350, how far does the bag slide before coming to rest

a

b

c

Explanation:

From the question we are told that

The mass of the bag is

The normal force experienced is

The maximum acceleration of the bag is

Generally this normal force experience by the bag is mathematically represented as

=>

=>

=>

=>

Generally for the bag not to slip , it means that the frictional force is equal to the sliding force

Hence is mathematically represented as

While is mathematically represented as

So

=>

=>

Generally from the workdone equation we have that

Here is the work done by friction which is mathematically represented as

Here s is the distance covered by the bag

is zero given that velocity at rest is zero

and

so

=>  

substituting  2.55 m/s for v_i and 0.350 for  \mu_k  we have that

=>

nah.   i'm just sleepy.

did yall get answers for this yet