a kangaroo jumps up with an initial velocity of 36 feet per second from the ground (assume its stating height is 0 feet). Use the vertical motion model, h= -16t+ vt+ s , where v is the inicial velocity in feet per second and s is the height in feet, to calculate the amount of time the kangaroo is in the air before it hits the ground again. Round you answer to the nearest tenth if necessary. Time in air:___ seconds

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.

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Ithink it is c ,i hope i you