Can somone help me with this problem I have been stuck on it for a while. The answer is 17.1m but I dont understand how to get it. If you dont know dont answer or I will report you.

Hi There, Buddy!

To solve this problem, let us divide the entire motion into 2 phases

1.) When the elevator is moving with an acceleration

2.) When the elevator has a deceleration

For the first half -

u = 0 , a = 0.6 , t = t1

v = 0.6(t1)   ( 1 )

s = 1/2 x 0.6 x (t1)^2 = 0.3(t1^2) ( 2 )

For the second half -

u = 0.6(t1) , a = -0.8 , v = 0

0.6 x (t1) = 0.8 (t2) > 3(t1) = 4(t2) ( 3 )

0.36(t1)^2 = 1.6 s2 ( 4 )

Now, we know that the total time taken is 10 seconds

t1 + t2 =10 , 3t1 = 4t2 t1 = 40/7 , t2 = 30/7

Now, substitute values of t1 and t2 in s1 and s2 and add both s1 and s2 to get total distance travelled.

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