"what is the horse's average velocity during the first ten seconds of its gallop

This question is incomplete

Explanation:

This question is incomplete. However, from the completed question, determine the distance (in meters) the horse covered in the first ten seconds of it's gallop and apply the formula below.

Average velocity = distance (in meters) ÷ time (in seconds as provided in this question)

The unit for velocity (to be used here) is m/s or ms⁻¹

learn it on the intertant so you can solve

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west