A student solving for the acceleration of an object has applied appropriate physics principles and obtained the expression a = a1 + Fm where a1 = 3.00 m/s2, F = 12.0 kg. m/s2 and m = 7.00 kg. First, which of the following is the correct step for obtaining a common denominator for the two fractions in the expression in solving for a? a. (m/m times a1/1) + (1/1 times F/m).
b. (1/m times a1/1) + (1/m times F/m).
c. (m/m times a1/1) + (F/F times F/m).
d. (m/m times a1/1) +(m/m times F/m ).

Aleaky 10-kg bucket is lifted from the ground to a height of 15 m at a constant speed with a rope that weighs 0.7 kg/m. initially the bucket contains 45 kg of water, but the water leaks at a constant rate and finishes draining just as the bucket reaches the 15-m level. find the work done. (use 9.8 m/s2 for g.) show how to approximate the required work by a riemann sum. (let x be the height in meters above the ground. enter xi* as xi.) lim n → ∞ n (9.8)(45−3 xi) i = 1 δx express the work as an integral. 0 dx evaluate the integral. (round your answer to the nearest integer.) j