A train can speed up at a uniform rate of 0.15 m/s2. In what minimum distance can it attain a speed of 25 m/s if it is starting from rest?

d = 2083.33 m

Explanation:

Given that,

Acceleration of the train, a = 0.15 m/s²

The initial speed of the car, u = 0\

Final velocity, v = 25 m/s

We need to find the minimum distance covered by the train. Let it is d. Using third equation of kinematics as follows :

So, the minimum distance is 2083.33 m

c

explanation:

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