An object starts from rest and accelerates uniformly. If it moves 2.00m during the first second, then, during the first 5.00 seconds, it will move:. a. 7.00 mm .
b. 10.0 mm .
c. 25.0 mm .
d. 50.0 mm .

The correct option 50.0 m (the units of the answers are wrong, they should be in meters and not in millimeters).  

Explanation:

From the first second we can find the acceleration of the object:

Where:

: is the final position = 2.00 m

: is the initial position = 0

: is the initial speed = 0 (starts from rest)

t: is the time = 1 s

The acceleration is:

Now, we can find the distance after 5 seconds:

Therefore, the correct answer is 50.0 m. All the options have the units in millimeters and not in meters hence, the units of the options are wrong.

I hope it helps you!        

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft