In the standing broad jump, one squats and then pushes off with the legs to see how far one can jump. Suppose the extension of the legs from the crouch position is 0.75 m and the acceleration achieved during the time the jumper is extending their legs is 1.1 times the acceleration due to gravity, how far can they jump?State your assumptions(increase range can be achieved by swimming the arms in the direction of jump).

0.825 m

Explanation:

Given that

Extension of the leg position, s = 0.75 m

Acceleration due to gravity, g = 9.81 m/s²

From the question, it is seen that he accelerated at 1.1 times higher than normal. This means that the acceleration is 1.1 * 9.81.

a = 10.79 m/s²

Now, using one of the equations of motion, we have

v² = u² + 2as, with the initial velocity, u being 0

v² = 2as

v² = 2 * 10.79 * 0.75

v² = 16.185

v = √16.185

v = 4.02 m/s

Next and finally, we find the speed by maximum height

H = (v² - u²)/2g

H = (0 - 4.02²) / (2 * -9.81)

H = -16.185/ -19.62

H = 0.825 m

air exerts forces on falling objects near earth’s surface.

explanation:

the term 'free falls' refer to object that are falling towards the earth, in a situation in which gravity is the only force acting on the object.

for an object in free fall, the acceleration is constant (g, the gravitational acceleration), and so the velocity of the object constantly increases.

for objects near earth's surface, there is always another force acting on the object: the resistance due to the air. this force is opposed to the direction of fall of the object, and it is proportional to the velocity of the object, so as the object falls down, this force increases up to a point when it balances the force of gravity, and the object continues its motion at constant velocity (called terminal velocity). since in this case gravity is not the only force acting on the object, we are not in a situation of free fall.