Physics, 20.09.2020 15:01 aashna66

1. A rocket hits the ground at an angle of 60° from the horizontal at a speed of 300 m/s. a.
Draw the vector representing the rocket's impact and its components
b. Calculate the horizontal and vertical components of the rocket's impact velocity
n (U. S.)

Answers: 3

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Answers

Answer from: sarahaziz9526

(a). The horizontal and vertical components are $v\cos\theta$ and $v\sin\theta$

(b). The horizontal and vertical components of the rocket's impact velocity is 150 m/s and 259.8 m/s.

Explanation:

Given that,

Angle = 60°

Speed = 300 m/s

(a). We need to draw the vector representing the rocket's impact and its components

Using given data

The components of rocket's impact

The horizontal component is

$u_{x}=u\cos\theta$

The vertical component is

$v_{v}=v\sin\theta$

(b). We need to calculate the horizontal and vertical components of the rocket's impact velocity

Using horizontal and vertical components

The horizontal component is

$v_{x}=v\cos\theta$

Put the value into the formula

$v_{x}=300\cos60$

$v_{x}=150\ m/s$

The vertical component is

$v_{x}=v\sin\theta$

Put the value into the formula

$v_{x}=300\sin60$

$v_{x}=259.8\ m/s$

Hence, (a). The horizontal and vertical components are $v\cos\theta$ and $v\sin\theta$

(b). The horizontal and vertical components of the rocket's impact velocity is 150 m/s and 259.8 m/s.

1. A rocket hits the ground at an angle of 60° from the horizontal at a speed of 300 m/s.

a.
Draw t

Answer from: Quest

layers of the earth affect the waves and these effects are seen on instruiments such as seimometers

Answer from: Quest

force is based upon mass and acceleration.the statement is not always true.

it can be explained from newton's second law of motion.

as per newton's second law of motion the rate of change of momentum is directly proportional to the applied force and takes place along the direction of force.

mathematically it can be written as -

$f\alpha \frac{dp}{dt}$

⇒ $f= k \frac{dp}{dt}$

here k is the proportionality constant whose value is 1.

$f=\frac{dp}{dt}$

$f= \frac{d[mv]}{dt}$

$f= m\frac{dv}{dt} +v\frac{dm}{dt}$

$f=ma+v\frac{dm}{dt}$ [a is the acceleration=dv/dt]

hence we see that force not only depends on mass and acceleration but also on velocity and rate of change of mass. force f will depend on mass and acceleration only when mass is constant.

hence the statement that force is based upon mass and acceleration is false.

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