The output of a automobile alternator is typically about 14V D. C. The headlight circuit draws about 4 Amps of current. Using Ohm's Law (V = IR), the resistance of the headlight bulb can be calculated. Suppose your alternator quits working as you are driving home. The battery voltage now supplying energy to the headlight bulb drops to 12V D. C. Assume the bulb resistance R remains constant (it won’t, but that is another story). Required:
How much current (in Amps) now flows through the bulb?

I = 3.42 A

Explanation:

Ohm's law gives a relationship between the potential difference and the current passing through a conductor. The formula of Ohm's Law is given as follows:

V = IR

where,

V = Voltage

I = Current

R = Resistance

Initially:

V = 14 volts

I = 4 A

R = ?

Therefore,

14 volts = (4 A)R

R = (14 volts)/(4 A)

R = 3.5 Ω

Now, when V becomes 12 volts and R remains constant:

V = IR

12 volts = I(3.5 Ω)

I = (12 volts)/(3.5 Ω)

I = 3.42 A

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.