3. A model rocket is launched straight upward at 58.8 m/s. a. How long does it take for the rocket to reach its peak height?
b. what is the total time of flight of the model rocket ?
c. what is the peak height of the rocket from the ground ?

a). 6 seconds

b). 12 seconds

c). 176.4 meters

Explanation:

a). Equation to be applied to calculate the time taken by the rocket to reach at the peak height,

   v = u - gt

where v = final velocity

u = initial velocity = 58.8 m per sec

g = gravitational pull = 9.8 m per sec²

t = duration of the flight

At the peak height,

v = 0

Therefore, 0 = 58.8 - (9.8)(t)

t =  

 = 6 seconds

b). Total time of flight = 2(Time taken to go up)

                                    = 2×6

                                    = 12 sec

c). Formula to get the peak height is,

   h = (58.8)6 -

      = 352.8 - 176.4

      = 176.4 meters

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.

it has to be b, about 97 percent.