A box is sitting on the floor. The box was then pulled with a force, Ft. The box did not move. The free-body
diagram of the box is shown.
Which describes the motion of the box based on the
resulting free-body diagram?
It is moving up with a net force of 20 N.
It is moving to the right with a net force of 10 N.
It is in dynamic equilibrium with a net force of O N.
It is in static equilibrium with a net force of O N.
F, = 20 N
F, = -10 N
F, = 10 N
F = -20 N

i think the answer would be b

see the picture for the vector

the magnitude of the vector by pythagorean theorem

r = √( (-10)^2 + (3)^2 ) = √109

magnitude = √109 units

the direction angle between vector and x-axis is

tan^(-1)(3/10) = 16.699

so the direction is approximately 16.7 degrees north of west

you can cut your hand off if your not

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j