The man pulls on the cord with a force of 350N. Represent this force acting on the support A, as a Cartesian vector and determine its direction

hi liqus here is ur ans;

Explanation:

End points of the cord are A(0m,0m,7.5m)and

B(3m,-2m,1.5 m)

r=(3m-0m)i + (-2m-0m)j + (1.5m-7.5m)k

=(3i-2j-6k)m

Magnitude=length of cord AB

r=(3m)2 +(-2m)2 +(-6m)2 = 7m

since you're a real machine, your ama is always less than your ima, because you can never totally eliminate friction.

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm