A proton starting from rest travels through a potential of 644 X 106V and then moves into a uniform magnetic field, B = 0.02 T, perpendicular to the protons velocity. What is the radius of the proton's resulting orbit in m? Mp 1.67 x 10-27 kg, e = 1.6 x 10-19 C.

Given :

Potential ,

Uniform magnetic field , B = 0.02 T .

Mass of proton , .

Charge on proton , .

Also , velocity of proton is perpendicular to magnetic field .

To Find :

The radius of the proton's resulting orbit .

Solution :

Now , when velocity is perpendicular to magnetic field radius of orbit is given by :

Putting all given values above :

Therefore , radius of orbit is 183.33 m .

Hence , this is the required solution .

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energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this