A cyclist is moving along a straight line with uniform acceleration. After travelling from 20 seconds, the velocity of the cyclist is 3.5 m/s. Find the acceleration of the cyclist.

a = 0.175 m/s^2

Explanation:

From newtons eauations of motion we know

v=u+at

here v= final velocity, u= initial velocity, a = acceleration, t= time

u = o( initialy object must be at rest)

therefore, 3.5 = 0+ a(20)

⇒ a = 3.5/20 =0.175 m/s^2

double the distance = divide strength by 4

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j