. The speedometer readings of a car are shown below. Find the acceleration of the car and its displacement. Time
9:25 am 9:45 am
Speedometer
36 km/h 72 km/h

It is given that u=36km/h

V= 72km/h

We have to convert it into m/s ao we will multiply it with 5/18

U=36×5/18=10

V=72×5/18=20

So acceleration =v-u/t

= 20-10/t

The time will be 9:45-9:25=20min

So we will convert it into second

= 20×60

a=20-10/20×60

=10/20×60

1/120

From  newtons 2nd law

V^2-u^2=2as

S=v^2-u^2/2a

=400-100×120/2

=18000m/s

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures