A box has a mass of 10.5 kg and has compressed a spring (with a spring constant of 71.7 N/m by 0.888m. The box is released from rest on a frictionless surface a. How fast is the box moving when it leaves the spring?

b. After the box has left the spring it comes to a surface with
Mk = 0.234 How fare does it slide on this surface before stopping?

c. Instead of sliding to a stop it only goes 0.432 m on the rough surface and then returns to a frictionless surface. How fast is it moving?

a. To find how fast it moves when it leaves the spring we use

1/2kx²= 1/2 mv²,

So making speed v subject

v=x√(k/m),

v= 0.888√(71.7/10.5) = 2.32 m/s

B) how far it goes after released

We know that

Work done = change in kinetic energy

So

(1/2 mv²0)= F x D,

F= mu x N,

But N=mg , F=0.234 x 10.5x 9.81= 24.10

So

0.5x 10.5 x 2.32 x 2.32= D x 24.10,

So

D= 1.17 m

C. Now using the work energy theorm:

0.5(mv1²- mv2²) =F xD = mu. mg x D

V2=√(V1²- 2gmu) =

√(2.32x 2.32-2 x 0.432 x 9.81 x 0.234) =

V2=1.8m/s

weather forecasts are done by collecting data about the current state of the atmosphere mainly the temperature, humidity and wind and using meteorology, to determine the atmosphere that evolves over time. the h and l mean the high and low pressure. the red strip is a warm front. the blue strip is a cold front. the blue and red strip is a stationary front. the purple strip is a occluded front.

explanation:

i think the answer would be reserve.