How many Joules are absorbed by a pot of water with a mass of 600 g in order to raise the temperature from 30° C to 40° C? (The specific heat of water is 4.184 J/g°C) *

25104 J

Explanation:

We are given;

Mass; m = 600 g

Change in temperature;Δt = (40 - 30) = 10°C

Specific heat of water; c = 4.184 J/g°C

Now, to find how many joules, we simply use the formula for quantity of heat.

Thus;

Q = mcΔt

Plugging in the relevant values to give;

Q = 600 × 4.184 × 10

Q = 25104 J

Quantity of heat = 25104 J

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