If Justin races his Chevy S-10 down highway 37 north for 2,560 meters in 60 seconds, what is his velocity? a. Draw Justin's trip. What are his distance and displacement? b. The Chevy S-10
started rounding at 10 meters per hour. What is the acceleration at 30 seconds on the
highway? c. The S-10 has a force of 30 N. What is the mass of the car?

A.) 42.7 m/s

B.) 0.33 m/s^2

C.) 90 kg

Explanation:

A.) If Justin races his Chevy S-10 down highway 37 north for 2,560 meters in 60 seconds, what is his velocity? 

Velocity = displacement/time

Velocity = 2560/60

Velocity = 42.67 m/s

B.) The Chevy S-10 started rounding at 10 meters per hour. What is the acceleration at 30 seconds on the highway?

Acceleration = velocity/time

Acceleration = 10/30

Acceleration = 0.33 m/s^2

C.) The S-10 has a force of 30 N. What is the mass of the car?

Force = mass × acceleration

30 = mass × 0.33

Mass = 30/ 0.33

Mass = 90 kg

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!

the maxium height is 34m/s