A car accelerates from rest to 90m/s in 3 seconds. What is the acceleration and how far did it travel?

Explanation:

1.)acceleration= final velocity-initial velocity/time

90m/s-0m/s /3seconds

=30m/s^2

2.) distance= speed*time

90m/s*3seconds

=270m

part 1: which substance has a higher solubility?

a

smallest amount left undissolved atall temps in table shown most has dissolved high sol'by

the tires are rotating at 0.434 rpmlinear speed=45 m/sdiameter=0.550 mradius=0.275 mnow v= rωω= v/rω=45/0.275ω=163.6 rad/sω=163.6 rad/s (1rev/2π rad) (60s/1m)ω=1563 rpm