Physics, 02.09.2020 18:01 aerisander02
The average speed during any time interval is equal to the total distance of travel divided by the total time. Let d represent the distance between A and B. Let t1 be the time for which she has the higher speed of 5.15 m/s = d/t1. Let t2 represent the longer time for the return trip at 2.80 m/s =d/t2. Then the times are t1 = d/5.15 5.15 m/s and t2 = d/2.80 2.8 m/s. The average speed vavg is given by the following equation. vavg = Total distance/Total time = d + d/t1 + t2.
Answers: 3
Physics, 22.06.2019 14:00
Amass attached to a spring is displaced from its equilibrium position by 5cm and released. the system then oscillates in simple harmonic motion with a period of 1s. if that same mass–spring system is displaced from equilibrium by 10cm instead, what will its period be in this case? a mass attached to a spring is displaced from its equilibrium position by and released. the system then oscillates in simple harmonic motion with a period of . if that same mass–spring system is displaced from equilibrium by instead, what will its period be in this case? a) 0.5sb) 2sc) 1sd) 1.4s
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How much energy is supplied to each coulomb of charge that flows through a 12-v battery?
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The average speed during any time interval is equal to the total distance of travel divided by the t...
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