A train is moving at a constant speed on a surface inclined upward at 15.0° with the horizontal and travels 300 meters in 5 seconds. Calculate the horizontal velocity of the train at the end of 3 seconds.

57,9 m/s

Explanation:

A train is moving at a constant speed on a surface inclined upward at 15.0° with the horizontal and travels 300 meters in 5 seconds. The horizontal velocity of the train at the end of 3 seconds is 100m/s.

The first formula we will use is:

v = d/t

300m ÷ 5s  = 60m/s

The last formula we will use is:

vh = v·cosx

60m/s·cos15.0°

60m/s · 0,965  = 57,9 m/s

Therefore, the answer is 57,9 m/s.

Hope this helped!

57,9 m/s

velocity formula

v = d/t

= 300m/5s

= 60m/s

horizontal velocity formula

vh = v·cosx

= 60m/s×cos15°

= 60m/s×0,965

= 57,9 m/s

answer: strength i guess

explanation:

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