A circular loop of wire 1.0 cm in radius carries a current of 40 A. The magnetic field at the center of the loop is

The magnetic field at the center of the loop is 2.51 × 10⁻³ T

Explanation:

The magnetic field at the center of a circular loop is given by

B = μ₀I/2r

Where B is the magnetic field strength in Teslas (T)

μ₀ is the permeability of free space

μ₀ = 4π ×10⁻⁷ N/A²

I is the current in Amperes (A)

and r is the radius of the loop in meters (m)

From the question,

r = 1.0 cm

Convert this to meter (m)

1.0 cm = 1.0 × 10⁻² m = 0.01 m

∴ r = 0.01 m

I = 40 A

Hence, the magnetic field at the center of the loop is

B = μ₀I/2r

B = (4π ×10⁻⁷ × 40) / (2 × 0.01)

B = 5.0265 × 10⁻⁵ / 0.02

B =  2.51 × 10⁻³ T

Hence, the magnetic field at the center of the loop is 2.51 × 10⁻³ T

force tends to be low and long diustance masses are high