What is the electric field at a location vector b = <-0.2, -0.4, 0> m, due to a particle with charge +3 nC located at the origin?

E = 134.85 N/C

Explanation:

We are given;

Electric field location; b = <-0.2, -0.4, 0> m

Charge: q = 3 nc = 3 × 10^(-9) C

From the location given, we have total distance;

r = √((-0.2²) + (-0.4)² + (0²))

r = √0.2

Formula for Electric field is;

E = kq/r²

where;

k is a constant with a value of 8.99 x 10^(9) N.m²/C²

q is charge on the proton particle with a costant value = 1.6 × 10^(-19) C

r is the distance

Plugging in the relevant values, we have;

E = (8.99 x 10^(9) × 3 × 10^(-9))/(√0.2)²

E = 134.85 N/C

the total distance that martina travels that day is

(distance from home to mom's office) plus (distance from mom's office to school)

plus (distance from school to library) plus (distance from library to friend's house)

plus (distance from friend's house to martina's house).

(we don't know what any of these distance actually is.)

answer///isobars;