In a compound microscope, the objective has a focal length of 1.0 cm, the eyepiece has a focal length of 2.0 cm, and the tube length is 25 cm. What is the magnitude of the overall magnification of the microscope?

The  value  is  

Explanation:

From the question we are told that

     The  focal length of the objective is  

    The  focal length of the eyepiece is  

    The  tube length is  

Generally the magnitude of the overall magnification is mathematically represented as

Where   is the objective magnification which is mathematically represented as

=>      

=>      

is the eyepiece magnification which is mathematically evaluated as

So

wavelength divides in half and speed stays the same.

it is a negative acceleration