water is boiling in a pan at 100c if heat is transferred to the pan at a rate of 2 kw how much water in kg will evaporate in 10min

The mass of water that will evaporate 2.857 kg.

Explanation:

Given;

temperature of the water, T = 100 c

rate of heat transfer,  H = 2 kW = 2000 w

time, t = 10 min = 10 min x 60s = 600s

heat capacity of water is given by;

Q = McΔT

Where;

Q is the quantity of heat transfer to the pan = P x t =  2000 x 600 = 1200000 J.

c is specific heat capacity of water = 4200 J/kg.°C

m = (Q) / (cΔT)

m = (1200000) (4200 x 100)

m = 2.857 kg

Therefore, the mass of water that will evaporate 2.857 kg.

hey , the answer is c