Suppose the tourist in question 1 instead threw the rockwith an initial velocity of 8.0m/s[down]determine the velocity and the displacement of the rock at4.0s[remember thev is down and must become a 8.0 m/s]

Given:

By using the relation, we get

→

By substituting the values, we get

hence,

→

Thus the above answer is appropriate.    

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The velocity of the rock is 47.24 m/s

The displacement of the rock is 110.48 m

Explanation:

The initial velocity u = 8.0 m/s

time t = 4.0 s

Using

where v is the final velocity of the rock after 4.0 s

u is the initial speed = 8 m/s

g is acceleration due to gravity = 9.81 m/s

t is the time = 4.0 s

substituting, we have

= 47.24 m/s

Also, using

where

s is the distance that the stone fell

t is the time = 4.0 s

g is the acceleration due to gravity = 9.81 m/s^2

substituting values, we have

s = 32 + 78.48

s = 110.48 m

need to see circuit to get time constant

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