an object is placed at a distance of 10cm from a convex mirror of focal length 15 cm find the position and nature of the image

Given:

Object distance (u) = -10 cm

Focal length (f) = 15 cm

To Find:

Image distance (v) and nature of the image

Explanation:

Mirror Formula:

Substituting values of u and f in the equation:

Image distance (v) = 6 cm

Nature of the image = Virtual and Erect

answer: point c: b. 1/2 potential, 1/2 kinetic, point a: 3/4 of its potential energy, point d or b: 3/4 potential, 1/4 kinetic

explanation: i cant explain. it's difficult to explain.

0.3x0.21x0.08kg=mass 1 sheet

mass 500 = 500xmass 1

volume pile = 0.3x0.2x0.048

density=mass/volume= 500xmass 1/0.3x0.2x0.048

v patient student