An air-filled capacitor consists of two parallel plates, each with an area of 8 cm^2 , separated by a distance 2.9 mm. A 22 V potential difference is applied to these plates. What is the magnitude of the surface charge density on each plate?

The magnitude of the surface charge density on each plate is 6.714 x 10⁻⁸ C/m²

Explanation:

Given;

area of the parallel plates, A = 8 cm² = 8 x 10⁻⁴ m²

distance between the plates, d = 2.9 mm = 0.0029 m

potential difference applied to the plates, V = 22 V

The electric field between the plates is given by;

The surface charge density is given by;

σ = ε₀E

σ = (8.85 x 10⁻¹²)(7586.207)

σ = 6.714 x 10⁻⁸ C/m²

Therefore, the magnitude of the surface charge density on each plate is 6.714 x 10⁻⁸ C/m²

when insulating materials rub against each other, they may become electrically charged . electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. the material that gains electrons becomes negatively charged. the material that loses electrons is left with a positive charge.

when it gains or loses electrons