In a photoelectric experiment, a metal is irradiated with light of energy 3.56 eV. If a stopping potential of 1.10 V is required, what is the work function of the metal?

The  work function is  

Explanation:

From the question we are told that

    The light energy is  

     The  stopping voltage is  

Generally work function is mathematically represented as

Where KE is the kinetic energy of the ejected electron and it is mathematically represented as

Where  e is the charge on the electron

So  

Thus  

=>      

c. magnitude and direction

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