Calculate the peak voltage of a generator that rotates its 200-turn, 0.100 m diameter coil at 3600 rpm in a 0.800 T field.

The peak voltage is 473.86 V

Explanation:

Given;

number of turns of generator, N = 200  turn

diameter of the coil, d = 0.1 m

radius of the coil, r = 0.05 m

Magnitude of the magnetic field, B = 0.8 T

angular frequency, ω = 3600 rpm

angular frequency, ω (rad/s) =

The peak voltage is given by;

E = NBAω

Where;

A is the area of the coil = πr² =  π (0.05)² = 7.855 x 10⁻³ m²

E = (200)(0.8)(7.855 x 10⁻³)(377.04)

E = 473.86 V

Therefore, the peak voltage is 473.86 V

okay i have so many questions. but the big one here is: um wt..f is this mess? ?

the moon affects the earth gravitation ally, causing certain motions of that body and also producing tides in its ocean and atmosphere. the tidal wave in our atmosphere is, however, far too minute to be an effective cause in any known meteorological phenomenon.

explanation: