The distance record for someone riding a motorcycle on its rear wheel without stopping is more than 320000 m. Suppose the rider in this unusual situation travels with an initial speed of 8.00 m/s before speeding up. The rider then travels 40.0 m at a constant acceleration of 2.00 m/s2. What is the rider’s speed after the acceleration?

  v = 15.0 m/s

Explanation:

This is an exercise in kinematics in one dimension

          v² = v₀² + 2 a x

in the exercise indicate that the initial velocity v₀ = 8.00 m / s

the distance traveled during acceleration is x = 40.0 m

let's calculate

          v² = 8² + 2 2 40

          v = √ 224

           v = 14.97 m / s

           v = 15.0 m/s

answer would be d.) i hope this

explanation:

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