An airplane is traveling at 400 mi/h. It touches down at an airport 2000 miles away. How long was the airplane airborne?

5 hours

Explanation:

Given that

Speed of the airplane, v = 400 mile/hr

Distance of the airport, s = 2000 miles

This is quite a straightforward question that deals with one of the basic formulas in physics.

Speed.

speed is said to the the ratio of distance covered with respect to the time taken. This can be mathematically expressed as

Speed, v = distance covered, d / time taken, t

v = d / t

In the question above, we're looking for the time taken. So, so make t, subject of formula.

t = d / v, now we proceed to substituting the earlier given values into this equation.

t = 2000 / 400

t = 5 hrs,

therefore we can conclude that the airplane was airborne for 5 hours

i don't understand. explain it clearly

i really dont know but i will try okay.

so i think u would just add all them up and get your answer..