A train starts from rest with acceleration of 0.5ms-2 find speed in Kmh-1 when it moved through 100m. (36kmh-1)

36km/h

Explanation:

since the acceleration of the train was 0.5m/s² i.e it is constant . since the acceleration is constant you can use one of the "SUVAT" equations to find the answer.

the equation that best fits this question is: v²=u² + 2āS.

v stands for final velocity

u stands for intial velocity

v²=u² + 2āS since the car started from rest the intial velocity is zero.

v²=u² + 2āS

v²= 0 + 2(0.5m/s²)*100m

v²= 1m/s²*100m

√v²=√100m²/s²

v=10m/s

1km/hr = 1/3.6m/s

x.= 10m/s.

use criss cross method to find the value of x

x=( 1km/hr* 10m/s)

1/3.6m/s

x= 36km/hr

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