Two resistors connected in parallel, with R1 = 150 ohms and R2 = 75 ohms, are connected to a battery that experiences a current of 0.18 A. The current through R1 is A.

Explanation:

Given:

Two resistors (Parallel)

R1 = 150 ohms

R2 = 75 ohm

Current (I) = 0.18 A

Find:

Current through R1

Computation:

Common resistance

1/R = 1/R1 + 1/R2

1/R = 1/150 + 1/ 75

R = 50 ohms

V = IR

V = 0.18 x 50

V = 9v

So,

V = IR1

9 = I (150)

Current through R1 = 9 / 150

Current through R1 = 0.06 A

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