Determine the orbital period (in hours) of an observation satellite in a circular orbit 1,787 km above Mars.

T = 3.14 hours

Explanation:

We need to find the orbital period (in hours) of an observation satellite in a circular orbit 1,787 km above Mars.

We know that the radius of Mars is 3,389.5 km.

So, r = 1,787 + 3,389.5 = 5176.5 km

Using Kepler's law,

M is mass of Mars,

So,

or

T = 3.14 hours

So, the orbital period is 3.14 hours