A mass m = 0.6 kg is released from rest at the top edge of a hemispherical bowl with radius = 1.1 meters. The mass then slides without friction down the inner surface toward the bottom of the bowl. At a certain point of its path the mass achieves a speed v = 3.57 m/s. At this point, what angle \theta\:θ ( in degrees) does the mass make with the top of the bowl?

The  angle is  

Explanation:

From the question we are told that

    The  mass is  

     The radius is  

     The speed is  

According to  the law of energy conservation

  The  potential energy of the mass at the top is equal to the kinetic energy at the bottom i.e

 =>    

Here h is the vertical distance traveled by the mass  which is also mathematically represented as

So

substituting values

float.

archimedes' principle

denser than water sinks in water.

denser than mercury would sink in it