A long, straight, horizontal wire carries a left-to-right current of 40 A. If the wire is placed in a uniform magnetic field of magnitude 3.7 ✕ 10−5 T that is directed vertically downward, what is the resultant magnitude of the magnetic field 22 cm above the wire (in T)?

The magnitude of the resultant of the magnetic field is

Explanation:

Given that,

Current = 40 A

Magnetic field

Distance = 22 cm

We need to calculate the magnetic field

Using formula of magnetic field

Where, r = distance

I = current

Put the value into the formula

We need to calculate the magnitude of the resultant of the magnetic field

Using formula of resultant

Put the value into the formula

Hence, The magnitude of the resultant of the magnetic field is

305.7

explanation:

density =m/v

density =917/3.00

density = 305.

approximately = 305.7

in four significant figures