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![25*10^{-6}C^{-1} =\frac{L_{1}-17.400}{17.400(100-20)}\\\\25*10^{-6}C^{-1} = \frac{L_{1}-17.400}{1392} \\\\L_{1}=[25*10^{-6}C^{-1} *1392}]+17.400\\\\L_{1}=17.435cm](/tpl/images/0717/9424/f0ab0.png)
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An aluminum rod 17.400 cm long at 20°C is heated to 100°C. What is its new length? Aluminum has a li...
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