What is the magnitude of the applied electric field inside an aluminum wire of radius 1.4 mm that carries a 4.5-A current

Explanation:

From the question we are told that

    The radius is  

     The  current is  

Generally the electric field is mathematically represented as

Where is the conductivity of  aluminum with value

J is the current density which mathematically represented as  

Here A is the cross-sectional area which is mathematically represented as  

So

So

less than one you can't create energy