A series LR circuit contains an emf source of 19 V having no internal resistance, a resistor, a 22 H inductor having no appreciable resistance, and a switch. If the emf across the inductor is 80% of its maximum value 4 s after the switch is closed, what is the resistance of the resistor

R = 394.36ohm

Explanation: In a LR circuit, voltage for a resistor in function of time is given by:

ε is emf

L is indutance of inductor

R is resistance of resistor

After 4s, emf = 0.8*19, so:

R = 394.36

In this LR circuit, the resistance of the resistor is 394.36ohms.

the entire statement is true and correct.  

there's no diagram, nothing is illustrated, and no question is asked.

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