The cylinder is displaced 0.17 m downward from its equilibrium position and is released at time t = 0. Determine the displacement y and the velocity v when t = 3.1 s. The displacement and velocity are positive if downward, negative if upward. What is the magnitude of the maximum acceleration?

Complete Question

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a

b

c

Explanation:

From the question we are told that

      The maximum  displacement is  A =  0.17  m  

      The  time considered is  

     The spring constant is  

      The mass is  

Generally given that the motion which the cylinder is undergoing is a simple harmonic motion , then the displacement is mathematically represented as

Where is the angular frequency which is mathematically evaluated as

substituting values

So the displacement is at  t

Generally the velocity of a  SHM(simple harmonic motion) is mathematically represented as

substituting values

Generally the maximum acceleration is  mathematically represented as

substituting values

substituting values

there was no answer choices but i think its representative