A particle undergoes damped harmonic motion. The spring constant is 100 N/m, the damping constant is 8.0 x 10-3 kg. m/s, and the mass is 0.050 kg. If the particle starts at its maximum displacement, x = 1.5 m, at time t = 0. What is the amplitude of the motion at t = 5.0 s?

The amplitude

Explanation:

From the question we are told that

     The  spring constant is  

      The  damping constant is  

       The mass is  

       The  maximum displacement is

       The  time  considered is  t =  5.0 s

Generally the displacement(Amplitude) of damped harmonic motion is mathematically represented as

substituting values

the answer is 46 mls because when you add the speed per second it increses the speed

answer; i believe that the correct answer is (d) a very small amount of mass