A uniform metre rod of 5 metre length is suspended horizontally by two strings P and Q. Pis attached 0.8 metre from one end and Q is attached 2 metre from the other end. Given that the weight of the rod is 110N. Calculate the tension in each string

The tension in string P is 25 N, while that of Q is 85 N.

Explanation:

Considering the conditions for equilibrium,

i. Total upward force = Total downward force

                      + = 110 N

ii. Taking moment about P,

clockwise moment = anticlockwise moment

110 × (2.5 - 0.8) = × (3 - 0.8)

110 × 1.7 = × 2.2

187 = 2.2

=

= 85 N

From the first condition,

+ = 110 N

+ 85 N = 110 N

= 110 - 85

25 N

Therefore, the tension in string P is 25 N while that of Q is 85 N.

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