A ballistic pendulum consists of a 4 kg wooden block originally at rest at θ = 0o . When a 2 g bullet strikes and becomes embedded it, it is observed that the block swings upward to a maximum angle of θ = 6o . Estimate the speed of the bullet just before the impact.

733m/s

Explanation:

Assuming that Just after impact:

given that at lowest point Is

T2 + V2 = T3 + V3

1 /2(4 + 0.002) (vB)²2 + 0 = 0 + (4 + 0.002)(9.81)(1.25)(1 -cos 6°)

(vB)2 = 0.3665

m>s For the system of bullet and block: ( S+ ) Σmv1 = Σmv2 0.002(vB)1 = (4 + 0.002)(0.3665) (vB)1 = 733 m/s

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