Find the rms (a) electric and (b)magnetic fields at a point 2.00 m from a lightbulb that radiates 90.0 W of light uniformly in all directions.

a) rms of electric field =

= 25.97 V/m

b) rms of magnetic field

= 8.655 × 10⁻⁸

= 86.55nT

Explanation:

given

power p = 90.0W

distance d = 2.00m

Intensity =

I =

A =

I =

I =

I = 1.79 W/m²

a) = ε₀ × × c

where ε₀ is permittivity of free space = 8.85×10⁻¹²,   is the root mean value and c is speed of light = 3×10⁸m/s

1.79 = 8.85×10⁻¹² × × 3×10⁸

=

= 674.1996

= 25.97 V/m

b)for rems magnetic field

= c

=

=

= 8.655 × 10⁻⁸

= 86.55nT

answer: a) y=-8x+5

a) m= -8

b) m= -2

c) m= 7

d) m= 6

a) electrical > light, sound, and thermal< < < <

) the mechanical energy of the firefighter moving.< < < < a) electrical > light, sound, and thermal< < < <

c) both a and b.